Kei Nishikori and Stan Wawrinka will meet in the Australian Open quarter-finals, after respective victories on Monday.
Kei Nishikori and defending champion Stan Wawrinka will meet in the Australian Open quarter-finals after respective victories on Monday.
Fifth seed Nishikori was largely untroubled as he got past ninth seed David Ferrer in straight sets, winning 6-3 6-3 6-3.
The US Open finalist was the aggressor, tallying 43 winners to Ferrer's 14, and only dropping serve once.
Third seed Wawrinka had a much tougher time as he needed four sets to see off Guillermo Garcia-Lopez.
In 2014, Garcia-Lopez was Wawrinka's reminder that grand slam tennis was not all plain sailing when the Spaniard beat him in the first round at the French Open.
This year, Wawrinka reminded Garcia-Lopez of the status quo - the Swiss was the title-holder, the Spaniard was in new territory.
Never before had Garcia-Lopez reached the fourth round at Melbourne Park, like Wawrinka had never won a major 12 months back.
But Garcia-Lopez did not create his own history, Wawrinka instead added to his own remarkable narrative in Australia - the fourth seed progressing 7-6 (7-2) 6-4 4-6 7-6 (10-8) in three hours two minutes.
Garcia-Lopez blew a gilt-edged opportunity to take the clash to five sets when he held five set points in the fourth-set tie-break, but he could not convert.